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信息与计算科学 数学与信息工程学院
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计算机科学与技术 数学与信息工程学院
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计算机科学与技术 数学与信息工程学院
信息与计算科学 数学与信息工程学院
SOLUTION 1 Begin with x 3 y 3 = 4 Differentiate both sides of the equation, getting D ( x 3 y 3) = D ( 4 ) , D ( x 3) D ( y 3) = D ( 4 ) , (Remember to use the chain rule on D ( y 3) ) 3x 2 3y 2 y' = 0 , so that (Now solve for y' ) 3y 2 y' = 3x 2, and Click HERE to return to the list of problems SOLUTION 2 Begin with (xy) 2 = x y 1 Differentiate both sides.
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SOLUTION 15 Since the equation x 2 xy y 2 = 3 represents an ellipse, the largest and smallest values of y will occur at the highest and lowest points of the ellipse This is where tangent lines to the graph are horizontal, ie, where the first derivative y'=0. Watch broadcasters, join a community, chat in real time, express your creativity. Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTube.
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Y ± y Í Ú Ô y Þ Ú Ô y ¶ p = y p Ô á y ¢ p = y p Ì ß y Ç _ ü ê Í ?. À r Ü y _ g } v C u } ª ¾ _ l « á ñ ¹ é Õ ë Ä µ å ñ « á ñ ¹ é ¼ 2 E } K À r Ü g } } ☐ « á ñ ¹ é b j 2 Ç ³ Ñ · y } j z Æ K y þ V } ª ¤. Use the Chain Rule to compute df/dx and df/dy (2) Repeat problem 1, but this time first finding the formula for the composite function f(g(x;.
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2 c ¤ c Ì Õ ¼ s Z Y Æ à É Õ ç ´ ) h y ¤ J J 7 Ö ¥ Û ª Q t y s Z c ¤ ò Ì º ê. Divide y, the coefficient of the x term, by 2 to get \frac{y}{2} Then add the square of \frac{y}{2} to both sides of the equation This step makes the left hand side of the equation a perfect square. Mathx=s3t/math math\frac{d}{ds}x^2=\frac{d}{ds}(s3t)^2/math math=2(s3t)/math math\frac{d^2}{ds^2}x^2=\frac{d}{ds}(\frac{d}{ds}x^2)/math math.
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计算机科学与技术 数学与信息工程学院
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计算机科学与技术 数学与信息工程学院